For what value of “k” will the equation (2kx2 + 5kx +2)=0 have equal roots?
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Answered by
10
d=0
b^2 -4ac=0
25k2-4(2K)(2)=0
25k2=16k
k=4/5
b^2 -4ac=0
25k2-4(2K)(2)=0
25k2=16k
k=4/5
Answered by
4
2kx² + 5kx +2 = 0
The quadratic equation has equal roots
⇒ the discriminant = 0
Solve x:
Discriminant = b² - 4ac
Given that a = 2k, b = 5k, c = 2
b² - 4ac = 0
(5k)² - 4(2k)(2) = 0
25k² - 16k = 0
k(25k - 16) = 0
k = 0 or 25k - 16 = 0
k = 0 or k = 16/25
Answer: k = 0 or k = 16/25
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