For what value of K are the roots of the quadratic equations Kx (x-2) + 10 = 10 real and equalFor what value of K are the roots of the quadratic equations Kx (x-2) + 10 = 10 real and equal
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Answer:
10
Step-by-step explanation:
kx^2 - 2kx +10=0
D=b^2-4ac
for real and equal root D= 0
0 = (-2k)^2 -. 4 × k × 10
0 =4k^2 -40 k
divide by 4
0= k^2 -10 k
divide by k
0= k-10
k= 10
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