Math, asked by sudu28, 1 month ago

For what value of K are the roots of the quadratic equations Kx (x-2) + 10 = 10 real and equalFor what value of K are the roots of the quadratic equations Kx (x-2) + 10 = 10 real and equal​

Answers

Answered by shrutizarekar093
0

Answer:

10

Step-by-step explanation:

kx^2 - 2kx +10=0

D=b^2-4ac

for real and equal root D= 0

0 = (-2k)^2 -. 4 × k × 10

0 =4k^2 -40 k

divide by 4

0= k^2 -10 k

divide by k

0= k-10

k= 10

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