Question

for what value of k does 2x^2+kx+3=0 have equal roots

Answer 1

Quadratic Equation : 2x^2 + kx + 3 = 0

Correction : for what value of k does 2x^2+kx+3=0 have equal and real roots

On comparing the equation with ax^2 + bx + c = 0, we get the following information :

a = 2  ,   b = k    ,     c = 3

Discriminant = b^2 - 4ac

For equal & real roots, b^2 - 4ac = 0

( k )^2 - 4( 2 × 3 ) = 0

k^2 - 24 = 0

k^2 = 24

k = √24

k = 2√6

Therefore, the value of k is 2√6

$\:$

Answer 2

Heya,


Given Equation is 2x^2+kx+3=0

For an equation to have two equal roots the following condition is necessary:

b^2-4ac=0, substituting the values of a,b and c we have,

K^2-4(2)(3)=0

K^2-24=0

K^2=24

Therefore K=root 24  ANSWER...

HOPE IT HELPS:-))