Math, asked by uma2211, 1 year ago

for what values of k does (k-12)x^2+2 (k-12)x+2=0 have equal roots

Answers

Answered by Sabir333
2
alpha + beta = alpha x beta
-b/a = c/a
-2(k-12)/(k-12) = 2/ (k- 12)
-2/1 = 2/ k-12
-2k + 24 = 2
-2k + 24 - 2 = 0
-2k + 22 = 0
-2k = -22
k = -22/-2 = -11

hope this helps u
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