For what value of k does the equation 12x2+4kx+3=0 has real and equal roots?
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Answered by
157
Hey
Here is your answer,
12x^2 + 4kx + 3 = 0
a = 12
b = 4k
c = 3
b^2 - 4ac = 0
(4k)^2 - 4 x 12 x 3 = 0
16k ^2 = 144
k^2 = 144/16
k^2 = 9
k = √9
k = 3
Hope it helps you!
Mark brainliest plz..
Here is your answer,
12x^2 + 4kx + 3 = 0
a = 12
b = 4k
c = 3
b^2 - 4ac = 0
(4k)^2 - 4 x 12 x 3 = 0
16k ^2 = 144
k^2 = 144/16
k^2 = 9
k = √9
k = 3
Hope it helps you!
Mark brainliest plz..
Answered by
5
Answer:
the answer is K=3
Step-by-step explanation:
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