Question

For what value of k does the equation 3x-2y=4 and kx+4y+6=0 have infinitely many solutions ?

Answer 1

3 -2

---=------

k 4

=》--2k= 4×3

k= 4×3

----------

--2

=--6

Answer 2

Answer:

Given eqns;

3x-2y=4 (3x-2y-4=0)

kx+4y+6=0

Step-by-step explanation:

• a1/a2= 3/k
• b1/b2= -1/2
• c1/c2= -2/3

For infinitely many solutions;

a1/a2=b1/b2=c1/c2

i.e., 3/k= -1/2

therefore by cross multiplication;

• -k= 6
• since -k=6, k= -6