for what value of k does the equation x+2x+k2+1=0 has real and equal roots?
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Heya friend!!
Here's ur ans with solution :)
✴✴As we know that if the quadratic equation has equal and real roots then it's discriminant will be equal to zero.
So, D = 0
and also
D = b²- 4ac .....( i )
☣ Here,
a = 1
b = 2
c = k² + 1
putting dis value on equation ( i )
D = b² - 4ac
0 = (2)² - 4 × 1 × ( k² + 1 )
0 = 4 - 4k² -4
0 = 4k²
0 = k²
k = 0
☢So, for the value of k = 0
the quadratic equation has real and equal roots.
@Altaf
Here's ur ans with solution :)
✴✴As we know that if the quadratic equation has equal and real roots then it's discriminant will be equal to zero.
So, D = 0
and also
D = b²- 4ac .....( i )
☣ Here,
a = 1
b = 2
c = k² + 1
putting dis value on equation ( i )
D = b² - 4ac
0 = (2)² - 4 × 1 × ( k² + 1 )
0 = 4 - 4k² -4
0 = 4k²
0 = k²
k = 0
☢So, for the value of k = 0
the quadratic equation has real and equal roots.
@Altaf
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