for what value of k does the equation X square + 2 X + K square + 1 is equal to zero has real and equal roots
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x²+2x+(k²+1)
here
a=1
b=2
c=k²+1
when Discriminant will be zero than we get real and equal roots
SO,
D=b²-4ac
0=(2)²-4(1)(k²+1)
0=4-4k²-4
0=4-4-4k²
0=-4k²
k²=0
k=0
HOPE IT WILL HELP YOU PLZZ MARK AS BRAINLIEST
here
a=1
b=2
c=k²+1
when Discriminant will be zero than we get real and equal roots
SO,
D=b²-4ac
0=(2)²-4(1)(k²+1)
0=4-4k²-4
0=4-4-4k²
0=-4k²
k²=0
k=0
HOPE IT WILL HELP YOU PLZZ MARK AS BRAINLIEST
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