For what value of K does the point (k, −3) lies on the line 3x − y = 6
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Answered by
18
y=-3
x=k
substituting the values of x,y in the linear equation
3(k)-(-3)=6
3k+3=6
3k=6-3
3k=3
k=1
hope it helps you!!!
Answered by
32
Answer:
in the point (k,-3) , x=k and y= -3
3x − y = 6
3k − (-3)= 6
3k + 3 = 6
3k = 6-3 = 3
k = 3/3
k = 1
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