Question

For what value of k does the system of equations x+2y=3 and 5x+ky+7=0 have a unique solution
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Answer 1

Answer:

put the value of y=1

Step-by-step explanation:

then X+2×1=3

X=1and y=1

5x+KY+7=0

5×1+k×1+7=0

5+1k+7=0

13+1k=0

k=-13