Question

For what value of k for which the quadratic equation
(k - 12)x2 + 2(k - 12)x+ 2 = 0 has real and equal roots
a) k = 0
b) k = -12
c) k = 14
d) k = 1​

Answer 1

Answer:

k=1 is the answer

I hope it helps

Step-by-step explanation:

kx²-12x²+2kx-12x+2=0

x²(k-12)+2(kx-6x+1)=0

(x²+2)=0. (k-12)(kx-6x+1)=0

x²=-2. k²x-6kx+k-12kx+72x-12

x²=-2. k²x-18kx+72x-12

x=√2.