Question

For what value of k, is (+1) is a factor of
$p(x) = k {x}^{2} - x - 4$
With steps needed

Answer 1

P(x) = kx²-x-4

P(1) = k×(1)²-(1)+4 = k-1+4


k = -3

Answer 2

$hii \\ \\ here \: is \: your solutin \: \\ \\ given \: that \: x = + 1 \\ \\ p(x) = p(1) = k \times {1}^{2} - 1 - 4$


$k - 1 - 4$
$\\ k = - 4 + 1$

$k = - 3$

$hope \: it \: helps \: you$