for what value of k is - 3 a zero of the polynomial x^2+11x+k
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p(x)=x^2+11x+k
p(-3)=0 (given)
substituting in the given polynomial we get
(-3)^2+11*-3+k=0
9-33+k=0
-24+k=0
k=24
p(-3)=0 (given)
substituting in the given polynomial we get
(-3)^2+11*-3+k=0
9-33+k=0
-24+k=0
k=24
siddharthverma1:
thanks kishore
Answered by
3
Hope this helps u
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