for what value of k is -4 a zero of polynomial x^2-x-(2k+2)
Answers
Answered by
16
Hiii friend,
it is given that -4 is a factor of the given polynomial.
P(X) = X²-X-(2K+2)
P(-4) = (-4)² - (-4)- (2K+2)
=> 16 + 4 -2K -2
=> 20-2K-2 = -18
=> -2K = -18
=> K = -18/-2
=> K = 9
HOPE IT WILL HELP YOU...... :-)
it is given that -4 is a factor of the given polynomial.
P(X) = X²-X-(2K+2)
P(-4) = (-4)² - (-4)- (2K+2)
=> 16 + 4 -2K -2
=> 20-2K-2 = -18
=> -2K = -18
=> K = -18/-2
=> K = 9
HOPE IT WILL HELP YOU...... :-)
riyagupta2656:
sorry ! but u did it wrong
Answered by
11
⭐⭐Hello friend..Ur answer is here⤵⤵
⚫ x^2-x-(2k+2)
If -4 is a zero of above polynomial then it satisfies it
➡(-4)^2-(-4)-(2k+2)=0
➡ 16+4-(2k+2)=0
➡(2k+2)=20
➡2k=18
➡k=9
I HOPE IT IS HELPFUL TO YOU ☺
⚫ x^2-x-(2k+2)
If -4 is a zero of above polynomial then it satisfies it
➡(-4)^2-(-4)-(2k+2)=0
➡ 16+4-(2k+2)=0
➡(2k+2)=20
➡2k=18
➡k=9
I HOPE IT IS HELPFUL TO YOU ☺
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