Math, asked by riyagupta2656, 1 year ago

for what value of k is -4 a zero of polynomial x^2-x-(2k+2)

Answers

Answered by Panzer786
16
Hiii friend,

it is given that -4 is a factor of the given polynomial.

P(X) = X²-X-(2K+2)

P(-4) = (-4)² - (-4)- (2K+2)

=> 16 + 4 -2K -2

=> 20-2K-2 = -18

=> -2K = -18

=> K = -18/-2

=> K = 9

HOPE IT WILL HELP YOU...... :-)

riyagupta2656: sorry ! but u did it wrong
Answered by Anonymous
11
⭐⭐Hello friend..Ur answer is here⤵⤵

⚫ x^2-x-(2k+2)

If -4 is a zero of above polynomial then it satisfies it

➡(-4)^2-(-4)-(2k+2)=0

➡ 16+4-(2k+2)=0

➡(2k+2)=20

➡2k=18

➡k=9

I HOPE IT IS HELPFUL TO YOU ☺
Similar questions