Question

For what value of k is the polynomial (2x^3x^3+2kx^2+3x+6) exactly divisible by (x-2)

Answer 1

Answer:

k=-140/8

Step-by-step explanation:

x-2=0

x=2

Substitute x as 2.

p(x)=2x^3x^3+2kx^2+3x+6

p(2)=2(2)^3(2)^3+2k(2)^2+3(2)+6

=2(8)(8)+2k(4)+6+6

=2(64)+8k+12

=128+8k+12

=8k +140

Now, 8k+140=0

8k=-140

k=-140/8

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