Question

for what value of k is the polynomial P(x) = 2x^3-kx^2+3x+10 exactly divisible by (x+2)?
(a) -1/3
(b) 1/3
(c) 3
(d) -3​

Answer 1

Answer:

Step-by-step explanation: if p(x) is exactly divisible by (x+2)

Then this will put p(x)=0

Now x+2=0

So, x = -2

p(x)=2x^3-kx^2+3x+10 =0

Put x= -2

p(-2)=2(-2)^3-k(-2)^2+3(-2)+10 =0

=2(-8)-k(4)-6+10 =0

=-16-4k-6+10 =0

=-22+10-4k =0

=-12-4k =0

So, -12=4k

Then k= -12÷4 = -3

Hope this will help u

Answer 2

Answer:

(d)-3

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