Question

For what value of k is x-1 a factor of x^2-6x+k ?

Answer 1

Your answer ⤵

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$x - 1 = 0 \\ \\ x = + 1 \\ \\ {x}^{2} - 6x + k = 0 \\ \\ {1}^{2} - 6 ( 1 ) + k = 0 \\ \\ 1 - 6 + k = 0 \\ \\ - 5 = - k \\ \\ k = 5$

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Answer 2

Hey here is your answer..... Hope it's help you