Hii frndss, pls answer this question quickly!!!
Show that the square of an odd positive integer can be of the form 6q+1 or 6q+3 foir some integer q.
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here is your answer
Let us look at the positive numbers generated by 6q + 1, so we have to start with the non negative integer 0, then input 1, 2, 3…
1, 7, 13, 19…
Now for 6q + 3:
3, 9, 15, 21…
Now for 6q + 5:
5, 11, 17, 23…
Add the three series, and you get all the the positive odd integers:
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23…
All positive integers are generated by one of the three formulas you gave.
I hope I help you
Let us look at the positive numbers generated by 6q + 1, so we have to start with the non negative integer 0, then input 1, 2, 3…
1, 7, 13, 19…
Now for 6q + 3:
3, 9, 15, 21…
Now for 6q + 5:
5, 11, 17, 23…
Add the three series, and you get all the the positive odd integers:
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23…
All positive integers are generated by one of the three formulas you gave.
I hope I help you
vikram991:
Dividing a positive odd number by an even number will result in an odd remainder. This can be easily shown. The only possible odd remainders for 6 are 1,3,5. Hence any positive odd number should be of the form mentioned in the question.
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