For what value of k(k>0) is the area of the triangle with vertices (-2, 5), (k, -4) and (2k+1, 10) equal to 53 square units?
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Answer: Using Heron's Area Formula Find the area of the triangle shown below. .... The seven-place tables give tabulated values for 5 significant ... The versed sine is 1 - cos θ, so it approaches zero as the angle ..... For example, tan A/2 = k / sin(s - a), where k 2 = sin (s - a) sin (s - b) ... There are 10 identities in all.
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