Question

for what value of k, kx^2-24x+36=0has complete square​

Answer 1

Step-by-step explanation:

Sol.

kx^2-24x+36=0

kx^2-24x=0-36

kx^2-24x=-36

kx^2=-36+24x

k=-36+24x/x^2

k=-36+24x/x×x

we will cut x from x

so we get,

k=-36+24/x

k=-12/x

Thanks

Hope it will help you .

Answer 2

Answer:

I hope it would help you.

the answer is 4