For what value of k system of linear equation 5x +4y =2 and 8x + ky =37 have unique solution
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a1/a2 should not be equal to b1/b2
So
a1=5 a2=8
b1=4 b2=I
So 5/8 =4/k
Solving this
5k=32
k=32/5
So
Any value can satisfy this equation except k=32/5
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