Question

for what value of k, the equation x+y-4 =0 and 2x+ky=3 have no solutions​

Answer 1

for the given equations to have no solution,

$a1 \div a2 = b1 \div b2 \: is \: not \: eqal \: to \: c1 \div c2$

a1= 1 ; b1= 2

b1= 1; b2= k

c1= -3; c2=-4

Step-by-step explanation:

a1/a2 = b1/b2

1/2= 1/k

k= 2

Thus the value of k should be 2