Question

For what value of k the following pair of linear equation has infinite many solutions
Kx+4y-(K+8)=0
4x+Ky-4=0

Answer 1

Hey

Here is your answer,

We know that, for infinitely many solutions

a1/a2 = b1/b2 = c1/c2

Here, a1/a2 = k/4 ; b1/b2 = 4/k ; c1/c2 = -k-8/4

.`. k/4 = 4/k (to have infinitely many solution)

= k2 = 16

= k = +-4

according to the eqn, k = -4.

Hope it helps you!

Answer 2

Answer:

Step-by-step explanation:

We know that, for infinitely many solutions

a1/a2 = b1/b2 = c1/c2

Here, a1/a2 = k/4 ; b1/b2 = 4/k ; c1/c2 = -k-8/4

.`. k/4 = 4/k (to have infinitely many solution)

= k2 = 16

= k = +-4

according to the eqn, k = -4.