Question

For what value of k the following pair of linear equation has infinitely many solution 10x+5y-k-5=0. 20x+10y-k=0

Answer 1

Answer:

For infinitely many solutions,

a1/a2  =  b1/b2  =  c1/c2

therefore, 10/20 = 5/10 = (-k-5)/(-k)

⇒1/2 = -(k+5)/-(k)

⇒ 1/2  =  k+5/k

⇒  k =  2(k+5)

⇒  k = 2k + 10

⇒ -10= 2k - k

⇒ k = -10

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Answer 2

Answer:

For infinitely many solutions,

a1/a2  =  b1/b2  =  c1/c2

therefore, 10/20 = 5/10 = (-k-5)/(-k)

⇒1/2 = -(k+5)/-(k)

⇒ 1/2  =  k+5/k

⇒  k =  2(k+5)

⇒  k = 2k + 10

⇒ -10= 2k - k

⇒ k = -10

hope it helps

plz mark as brainliest

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