Question

For what value of k, the following system of equations has a unique solution x-ky=2 and 3x+2y= -5

Answer 1

Answer:

k=-1,x=-1,y=-1

Step-by-step explanation:

x-ky=2

(-1)-(-1)×(-1)=2

-1×-1+1=2

+1+1=2

2=2

Answer 2

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⎟⎟ ✪✪ ＱＵＥＳＴＩＯＮ ✪✪ ⎟⎟

For what value of k, the following system of equations has a unique solution x-ky=2 and 3x+2y= -5

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⎟⎟ ✰✰ ＡＮＳＷＥＲ ✰✰ ⎟⎟

a1x + b1y + c1 = 0 and

a2x + b2y + c2 = 0

will have a unique solution.

If a1/a2 ≠ b1/b2 in the given system of equations a1 = 1, b1 = -k, a2 = 3, b2 = 2

So a1/a2 ≠ b1/b2 means

1/3 ≠ -k/2 ☞ -k ≠ 2/3

So, k ≠ -2/3

So the system of equations will have a unique solution for k = R - (-2/3) .

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