for what value of k the following system of linear equation have unique solution 2 X + K is equals to 1 and 3 x minus 5 Y = 7
Answers
Answered by
52
Hii friend,
2X+KY = 1..........(1)
3X -5Y = 7...........(2)
These equations are in the Form of A1X+B1Y +C1 = 0 And A2X+B2Y+C2 = 0
Where,
A1 = 2 , B1 = K , C1 = -1
A2 = 3 , B2= -5 and C2 = -7
For unique solution we must have,
A1/A2 is not equal to B1/B2
2/3 not = K/-5
-5 × 2 = 3 × K
3K = -10
K = -10/3
2X+KY = 1..........(1)
3X -5Y = 7...........(2)
These equations are in the Form of A1X+B1Y +C1 = 0 And A2X+B2Y+C2 = 0
Where,
A1 = 2 , B1 = K , C1 = -1
A2 = 3 , B2= -5 and C2 = -7
For unique solution we must have,
A1/A2 is not equal to B1/B2
2/3 not = K/-5
-5 × 2 = 3 × K
3K = -10
K = -10/3
Inu11:
there should be k is not equal to 0
Similar questions