Question

for what value of k the given equation is a perfect square

Answer 1

use this equation to find k ...
${b}^{2} - 4ac = 0$

Answer 2

Answer:

The value of k is either 0 or 3.

Step-by-step explanation:

The given equation is

$(4-k)x^2+(2k+4)x+(8k+1)=0$

The equation $ax^2+bx+c=0$ is a perfect square if

$b^2-4ac=0$

$(2k+4)^2-4(4-k)(8k+1)=0$

$36k^2-108k=0$

$36k(k-3)=0$

$k=0,3$

Therefore the value of k is either 0 or 3.