for What value of k the given system of equation K×+2Y=5 and 3×+Y = 1 HAVE unique solution
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Step-by-step explanation:Assertion
kx+2y=5 and 3x+y=1 have a unique solution if k=1
Reason
x+2y=3 and 5x+ky+7=0 have a unique solution if k
=1
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