for what value of 'k ' the numbers 2K + 1 , 13 , 5k - 3 are three consecutive term of an A.P. plz answer fast it's urgent
Answers
Answered by
80
It is given it is an AP therefore ,
13=[(2k+1)+(5k-3)]/2
13=(2k+1+5k-3)/2
13=(7k-2)/2
26=7k-2
7k=28
k=4
13=[(2k+1)+(5k-3)]/2
13=(2k+1+5k-3)/2
13=(7k-2)/2
26=7k-2
7k=28
k=4
no anjali....... I u r wrong
thanks☺☺☺☺
Answered by
45
if these are three consecutive term of an a. p
therefore
difference between them will be equal.
therefore
13-(2k+1)=5k-3-13
13-2k-1=5k-16
-7k=-28
k=-28/-7=4
therefore value of k will be 4.
if my answer is helpful for you then please mark as brain list
therefore
difference between them will be equal.
therefore
13-(2k+1)=5k-3-13
13-2k-1=5k-16
-7k=-28
k=-28/-7=4
therefore value of k will be 4.
if my answer is helpful for you then please mark as brain list
Thanku
u r welcome barsa
Similar questions
2(3k+3) = (5k-3)+(2k+1)
⇒6k +6 = 7k -2
⇒k =8
according to question it is 5k -1
so,
2(3k+3) = (5k-1)+(2k+1)
⇒6k +6 = 7k
⇒k =6