two equal sides of an isosceles triangle are each 2 centimetre more than thrice the third side if the perimeter of triangle is 67 cm, find the lengths of it's sides
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Let the third side be y.
Then, the other 2 sides will be 3y+2 each.
Therefore, (3y+2)+(3y+2)+y = 67
or, 7y = 63
or, y = 9 cm.
The side lengths are 9 cm, 29 cm and 29 cm.
Then, the other 2 sides will be 3y+2 each.
Therefore, (3y+2)+(3y+2)+y = 67
or, 7y = 63
or, y = 9 cm.
The side lengths are 9 cm, 29 cm and 29 cm.
sudhanshu492:
wrong answer
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1
let third angle be 3x
perimeter of isosceles triangle= sum of all angles
67=2+2+3x
3x=67-4
3x=63
x=21cm
third angle be 3×21=63cm ans
perimeter of isosceles triangle= sum of all angles
67=2+2+3x
3x=67-4
3x=63
x=21cm
third angle be 3×21=63cm ans
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