For what value of k, the pair of linear equations
3x + y = 3 and 6x + K y = 8 does not have a solution .
Answers
Answered by
16
Answer:
3x+y=3
3x+y-3=0......(1)
6x+ky-8=0.....2
a1=3
a2=6
b1=1
b2=k
c1=-3
c2=-8
for no solution
a1/a2=b1/b2=/c1/c2
3/6=1/k
1/2=1/k
k=2
Answered by
16
Answer
The equation are
3x + 5y - 3 = 0 .....(1)
6x + ky - 8 = 0 ......(2)
Here, a¹ = 3, b¹ = 5,c¹ = -3
and a² = b, b² = k, c² = -8
The given system has no solution if
- a¹/a² = b¹/b² =/ c¹/c²
- 3/6 = 5/k =/ -3/-8
- 3k = 30
- k = 30/3
- k = 10
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