Question

for what value of k the points (k -2), (1 4) and (-3 16) in given order are collinear? ​

Answer 1

Answer:

x1=k ,y1=-2 ,x2=1 ,y2=4 ,x3=-3 ,y3=16

Area of triangle=0

Step-by-step explanation:

Area of triangle=0

=>1/2[x1*(y2-y3)+x2*(y3-y1)+x3*(y1-y2)]=0

=>1/2[k*(4-16)+1*(16-(-2))-3*(-2-4)]=0

=>1/2[-12k+18+18]=0

=>-12k=-36

=>k=36/12

=>k=3