For what value of k the system of equation kx+3y=1 , 12x+ky=2 has no solution.
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Answered by
11
Answer:
for no solution
a1/a2 = b1/b2 should not be equal to c1/c2
therefore
k/12 = 3/k should not be equal to 1/2
from this we conclude
k^2 = 36
k= +- 6
also,
k should not be equal to 6
therefore, k = -6
Answered by
18
Answer:
k= -6
because ,
if your value expression equal to negative number then you will have no solution.
I hope its help you
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