Math, asked by yashdhorde7777, 11 months ago

For what value of k the system of equation kx+3y=1 , 12x+ky=2 has no solution.

Answers

Answered by SAMSYTALE
11

Answer:

for no solution

a1/a2 = b1/b2 should not be equal to c1/c2

therefore

k/12 = 3/k should not be equal to 1/2

from this we conclude

k^2 = 36

k= +- 6

also,

k should not be equal to 6

therefore, k = -6

Answered by Anonymous
18

Answer:

k= -6

because ,

if your value expression equal to negative number then you will have no solution.

I hope its help you

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