Question

For what value of K the system of equations kx-y=2. 6x-2y=3 has infinitely many solutions? a) k=3. B) k not equal to 4. C). K=6. D). Does not exist

Answer 1

for infinite solutions :
k/6=-1/-2=-2/-3
k/6=1/2
k=6/2
k=3
option -a

Answer 2

For infinite no.of solutions ,we must have:

a1/a2=b1/b2=c1/c2

K/6=-1/-2=-2/-3

K/6=1/2=2/3

Since 1/2is not equal to2/3

Therefore,b1/b2is not equal to c1/c2

Thus the given system of eqns has infinitely many solutions if any value of K does not exist.