For what value of k the system of linear equations kx-4y=3, 6x-12y=9 has infinite no of soln
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To find the value of k we must find atleast one value of x and y .
So, Let x = 1
then, 6x - 12y = 9
6 (1) - 12y = 9
6 - 12y = 9
-12y = 9 - 6
-12y = 3
y = 3/-12
y = 1/-4
Then, x = 1 , y = 1/-4
kx - 4y = 3
k(1) - 4(1/-4) = 3
k + 1 = 3
k = 3 - 1
k = 2
Therefore the value of k will be 2 as to get infinite number of solutions.
So, Let x = 1
then, 6x - 12y = 9
6 (1) - 12y = 9
6 - 12y = 9
-12y = 9 - 6
-12y = 3
y = 3/-12
y = 1/-4
Then, x = 1 , y = 1/-4
kx - 4y = 3
k(1) - 4(1/-4) = 3
k + 1 = 3
k = 3 - 1
k = 2
Therefore the value of k will be 2 as to get infinite number of solutions.
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