For what value of k the year of equations kx+2y=3 and (5k-7)x+3y=1 Will have no solution
Answers
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
Answered by
0
Step-by-step explanation:
- kx+2y=3
- (5k-7)x+3y=1
- The equations have no solution
- therefore, k/5k-7=2/3
- 3k-10k=2(5k-7)
- 3k-10k= -14
- -7k=-14
- k=2
Similar questions