Question

For what value of k, will 1 /
be a root of 3 x2 - 13 x-k=0.​

Answer 1

Answer:

$p(x) = 3 {x}^{2} - 13x - k \\ p(1) = 3 {(1)}^{2} - 13(1) - k \\ = 3 - 13 - k \\ = - 10 - k \\ as \: 1 \: is \: the \: root \: of \: eq \: so \: p(1) = 0 \\ - 10 - k = 0 \\ k = - 10$