for what value of k will 2k+1,6k-1,5k+7 the first three term of anA.P.
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Hello friend!
As we all know , the difference between consecutive terms of AP is same.
So that means-
(6k-1)-(2k+1)=(5k+7)-(6k-1)
6k-1-2k-1 = 5k+7-6k+1
4k-2 = 8-k
4k+k=8+2
5k=10
k=2
Now that we have got the value of k , we can easily find out the terms.
2(2) + 1 = 5
6(2) - 1 = 11
5(2) + 7 = 17
Thus the terms are 5 , 11 and 17.
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