Question

For what value of k will following system of equations have unique solution ?
3x+y =1
(2k-1)+(k-1)y= 2k +1

Answer 1

for having unique solution
a1/a2 is not equal to b1/b2
3/2k-1 is not equal to 1/k-1
by cross multiplying
3×(2k-1) is not equal to 1×(k-1)
6k-3 is not equal to k-1
6k-k is not equal to-1+3
5kis not equal to 2
therefore k=all the real values except2/5