Question

for what value of k will K - 1 ,k + 3 and 3k - 1 are consecutive terms of an ap​

Answer 1

Answer:

k=4

Step-by-step explanation:

For the terms being consecutive terms of an AP,

k+3-(k-1)= 3k-1-(k+3)=common difference

2= 3k-1-k-3

= 2k-4

2k= 2+4

2k=8

k=4

For k=3, the given expressions will be the terms of an AP

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Answer 2

Answer:

For the terms being consecutive terms of an AP,

k+3-(k-1)= 3k-1-(k+3)=common difference

2= 3k-1-k-3

= 2k-4

2k= 2+4

2k=8

k=4

Step-by-step explanation: