For what value of k will k+9, 2k-1 and 2k +7 are the consecutive terms of
an A.P. ?
Answers
Answered by
3
Answer:
18
Step-by-step explanation:
2K-1 -(K+9) = 2K+7 - (2K-1)
2K-1 -K-9 = 2K+7 - 2K + 1
K-10 = 8
K = 18
MARKIT AS BRAINLIAST ANSWER
Answered by
1
Answer:
k = +18
Step-by-step explanation:
to prove that numbers are in A.P:
a2 - a1 = a3 -a2
so,
2k-1-(k+9) = 2k+7-(2k-1)
2k-1-k-9 = 2k+7-2k+1
k-10 = 8
k = +18.
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