Math, asked by prem2304, 10 months ago

For what value of k will k+9, 2k-1 and 2k +7 are the consecutive terms of
an A.P. ?​

Answers

Answered by sanyamshruti
3

Answer:

18

Step-by-step explanation:

2K-1 -(K+9) = 2K+7 - (2K-1)

2K-1 -K-9 =  2K+7 - 2K + 1

K-10 = 8

K = 18

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Answered by jayanthikak
1

Answer:

k = +18

Step-by-step explanation:

to prove that numbers are in A.P:

a2 - a1 = a3 -a2

so,

2k-1-(k+9) = 2k+7-(2k-1)

2k-1-k-9 = 2k+7-2k+1

k-10 = 8

k = +18.

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