Solve
(3+i√5) (3-i√5) / (√3+√2i ) - (√3-i√2)
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Answer:
0 + ( - 7√2 / 2 ) i
Step-by-step explanation:
( 3 + i √5 )( 3 - i √5 ) / ( √3 + √2 i ) - ( √3 - √2 i )
Use the formula of ( a + b )( a - b ) = a² - b²
⇒ [ ( 3 )² - ( i √5 )² ] / [ √3 - √3 + √2 i + √2 i ]
⇒ [ 9 - 5 i² ] / [ 2 √2 i ]
We know i² = - 1
⇒ [ 9 + 5 ] / [ 2√2 i ]
⇒ 14 / 2√2 i
⇒ 7 / √2 i
Now rationalise the denominator :
⇒ 7 / √2 i × √2 i / √2 i
⇒ 7√2 i / 2 i²
⇒ 7 √2 i / ( - 2 )
⇒ - 7 √2 i / 2
Thats the answer ... Hope it helps -_^
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Answer:
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