For what value of k will the equation x +5y-7=0 and 4x +20y +k=0 represent coincident lines?
Answers
Answered by
30
given equation of line
X+5y -7 = 0
a1x+b1y+c1 = 0
on comparing
a1 = 1
b1 = 5
c1 = -7
second line
4x+5y +k = 0
a2x+b2y+c2 = 0
on comparing
a2= 4
b2 = 20
c2 = k
for coincident line condition is
a1/a2 = b1/b2 = c1/c2
1/4 = 5/20 = -7/k
-7/k = 1/4
k = -28
thus value of k for which lines are coincident is -28
X+5y -7 = 0
a1x+b1y+c1 = 0
on comparing
a1 = 1
b1 = 5
c1 = -7
second line
4x+5y +k = 0
a2x+b2y+c2 = 0
on comparing
a2= 4
b2 = 20
c2 = k
for coincident line condition is
a1/a2 = b1/b2 = c1/c2
1/4 = 5/20 = -7/k
-7/k = 1/4
k = -28
thus value of k for which lines are coincident is -28
Answered by
17
ANSWER.
k=-28
hope this helps....
Attachments:
Similar questions