Math, asked by whatywhen, 7 months ago

For what value of k will the following equations have infinitely many solutions? 2x-3y=7,
(k+1)x+(1-2k)y=5k-4

Answers

Answered by amansharma264
7

Answer:

in this question we has apply infinitely many solution formula and solve

Attachments:
Answered by ThakurRajSingh24
14

SOLUTION :-

Given that,

Pair of Linear equations,

i) 2x +3y=7

ii) (k+1)x+(2k-1)y=4k+1

We know that,

For infinite solutions :

a1/a2 = b1/b2 = c1/c2

From above equations,

a1 = 2 , a2= 3 , a3= 7

b1= k + 1 , b2 = 2k - 1 , b3 = 4k + 1

2/K+1 = 3/2k-1 = 7/4k+1

2/k + 1 = 3/2k - 1

4k - 2 = 3k + 3

.°. k = 5

So, the value of k is 5.

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