for what value of k will the following equations represent concident lines?2x+3y=4;4x+(k+4)y=3k+2
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Answer:
k=2
Step-by-step explanation:
put x = 1/2 , y = 1 in your equation..
then
2x + 3y = 4
2x1/2 + 3x1 =4
1 + 3 = 4
L.H.S = R.H.S (proof)
put your value of x and y in your 2nd equation
4x+(k+4)y = 3k+2
- 4x1/2 + k+4 = 3k+2
- 2+k+4 = 3k+2
- 2k = 4
k= 2
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