for what value of k will the following system have unique solution 2x+3y=4,(k+2)x+6y=3k+2
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Explanation:
2x+3y=4, (k+2)x+6y=3k+2
According to the question, the following equations have a unique solution.
So, a1/a2is not equal to b1/b2.
a1=2, b1=3 and a2=k+2, b2=6
a1/a2=1/k+2 and b1/b2=k+2/6
therefore when k=6 the equations have a unique solution.....
Hope It Helps........
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