For what value of k will the terms (2k+1),8 and 3k from an AP
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we know that to form an Ap the common differences will be same.
so 8-(2k+1)=3k-8
=>8-2k-1 = 3k-8
=>-5k =-15
=>5k=15
=>k=3.
so the value of k will be 3.
Ap will be 7,8,9
plz follow me and thank me if it helps
so 8-(2k+1)=3k-8
=>8-2k-1 = 3k-8
=>-5k =-15
=>5k=15
=>k=3.
so the value of k will be 3.
Ap will be 7,8,9
plz follow me and thank me if it helps
Sivakumarhct:
Thanks for ur answer bro....
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