For what value of k,x-2 is a factor of p(x)= kx²-4x+k?
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Answered by
2
Hi friend!!
Given, x-2 is a factor of p(x)= kx²-4x+k
Then p(2) must be equal to 0
→k(2)²-4(2)+k=0
4k-8+k=0
5k=8
k=8/5
I hope this will help u ;)
Given, x-2 is a factor of p(x)= kx²-4x+k
Then p(2) must be equal to 0
→k(2)²-4(2)+k=0
4k-8+k=0
5k=8
k=8/5
I hope this will help u ;)
sagarboss1:
wrong hai
Answered by
0
Answer:
Hi mate,
so the answer is:-
Step-by-step explanation:
(i) x-2 =0
therefore, x= 2
(ii) p(2)= k×2²- 4×2 + k = 0
∴ 4k - 8 + k = 0
∴ 4k + k = 8
∴ 5k = 8
∴ k = 8/5
∴ k = 1.6
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