Math, asked by vermapranav001, 1 year ago

For what value of k,x-2 is a factor of p(x)= kx²-4x+k?

Answers

Answered by DhanyaDA
2
Hi friend!!

Given, x-2 is a factor of p(x)= kx²-4x+k

Then p(2) must be equal to 0

→k(2)²-4(2)+k=0

4k-8+k=0

5k=8

k=8/5

I hope this will help u ;)

sagarboss1: wrong hai
DhanyaDA: u did it wrong actually. once check it
sagarboss1: ya you right
DhanyaDA: ^_^
sagarboss1: thnx for say me recheck
DhanyaDA: my pleasure
sagarboss1: again thnx
Answered by mdassirali1234
0

Answer:

Hi mate,

so the answer is:-

Step-by-step explanation:

(i) x-2 =0

therefore, x= 2

(ii) p(2)= k×2²- 4×2 + k = 0

∴ 4k - 8 + k = 0

∴ 4k + k = 8

∴ 5k = 8

∴ k = 8/5

∴ k = 1.6

Similar questions