For what value of 'k', x2 + 7x + (k + 1) polynomial zero is '1'.
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Answer:
k=-9
Step-by-step explanation:
given equation x^2+7x+(k+1)
and given equation have solution (zero) 1
then we substitute the value 1 in equation that will be equal to zero
i.e. (1)^2+7(1)+(k+1)=0
1+7+k+1=0
k+9=0
k=-9
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