Question

Ten years ago,A's age was half of B's age.If the ratio of their present ages is 3:4,what will be the sum off their present ages?

Answer 1

Answer:

Step-by-step explanation:

Let a's age be x

b's age be y

Ten yrs ago

(x-10),(y-10)

x-10=1/2(y-10)

2x-20=y-10

2x-y=10

x/y=3/4

4x=3y

Substituting the value

2x-4x/3=10

6x-4x=30

x=15

so,y=4(15)/3=20

x=15 y=20

Answer 2

Answer:

35

Step-by-step explanation:

x +10/2x +10=3/4

4x +40=6x +30

x=5